2y^2+5y=88

Solution for 2y^2+5y=88 equation:

2y^2+5y=88

We move all terms to the left:

2y^2+5y-(88)=0

a = 2; b = 5; c = -88;
Δ = b2-4ac
Δ = 52-4·2·(-88)
Δ = 729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{729}=27$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-27}{2*2}=\frac{-32}{4}
=-8
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+27}{2*2}=\frac{22}{4}
=5+1/2
$